2t^2/5=t/5+1/32

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Solution for 2t^2/5=t/5+1/32 equation: 


t in (-oo:+oo)

(2*t^2)/5 = t/5+1/32 // - t/5+1/32

(2*t^2)/5-(t/5)-(1/32) = 0

(2*t^2)/5-(t/5)-1/32 = 0

2/5*t^2-1/5*t-1/32 = 0

DELTA = (-1/5)^2-(-1/32*2/5*4)

DELTA = 9/100

DELTA > 0

t = ((9/100)^(1/2)+1/5)/(2/5*2) or t = (1/5-(9/100)^(1/2))/(2/5*2)

t = 5/8 or t = -1/8

t in { -1/8, 5/8 }

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